Question 357638
Determine the nature of the solutions of the equation. 

x^2 - 4x + 6 = 0 
a = 1 ; b = -4 ; c = 6
The equation has one real solution, two real solutions, or two non real solutions????
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b^2-4ac = 16 - 4*1*6 < 0
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Ans: 2 non real solutions.
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Cheers,
Stan H.