Question 357581
We will use point-slope form to form this equation. <br>

We can easily find the slope to be<br>

{{{(4-1)/(3-2)}}} which is {{{3/1}}}<br>

So the slope m=3<br>

Then we use point-slope form which is<br>

{{{y-y1=m(x-x1)}}}<br>

So using m=3 and the point (2,1) we have<br>

{{{y-1=3(x-2)}}}<br>

{{{y=3x-6+1}}}<br>

{{{y=3x-5}}} this is slope-intercept form<br>

{{{3x-y=5}}} this is standard form<br>

I hope this helps!<br>