<PRE><B>Question 357615</B>
To find this out, let&#39;s put this into solvable form: &lt;br&gt;

{{{x^2-6=0}}}&lt;br&gt;

{{{x^2=6}}}&lt;br&gt;

It should be apparent at this point that we will have two real solutions, and those two solutions would be&lt;br&gt;

{{{sqrt(6)}}} and {{{-sqrt(6)}}}&lt;br&gt;

I hope this helps!&lt;br&gt;</PRE>