Question 357569
Let the large number be x. <br>

Let the smaller number be y.<br>

Therefore, we are given<br>

{{{x+y=2(x-y)}}} and {{{x=2y+8}}}<br>

{{{x+y=2x-2y}}} and {{{x=2y+8}}}<br>

{{{x=3y}}} and {{{x=2y+8}}}<br>

Then we must solve this system of equations.  So by substitution<br>

{{{3y=2y+8}}}<br>

{{{y=8}}}<br>

If y=8 then<br>

{{{x=(2*8)+8}}}<br>

{{{x=24}}}<br>

<b>The larger number is 24, the smaller number is 8.</b><br>

I hope this helps!<br>