Question 357480


{{{2x^2=200}}} Start with the given equation.



{{{x^2=(200)/(2)}}} Divide both sides by {{{2}}}.



{{{x^2=100}}} Reduce.



{{{x=""+-sqrt(100)}}} Take the square root of both sides.



{{{x=sqrt(100)}}} or {{{x=-sqrt(100)}}} Break up the "plus/minus" to form two equations.



{{{x=10}}} or {{{x=-10}}}  Take the square root of {{{100}}} to get {{{10}}}.



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Answer:



So the solutions are {{{x=10}}} or {{{x=-10}}}.