Question 357281
32 = 4 * 8 = 4 * (2^3)


108 = 4 * 27 = 4 * (3^3)


3[cbrt(32)] = 3 * 2[cbrt(4)] = 6 cbrt(4)


7[cbrt(108)] = 7 * 3[cbrt(4)] = 21 cbrt(4)


subtracting gives ___ -15 cbrt(4)



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