Question 357227
30-60-90 triangles have sides in {{{1/2}}}-{{{sqrt(3)/2}}}-{{{1}}} proportion.
{{{(sqrt(3)/2)X=22}}}
{{{X=44/sqrt(3)=(44/3)sqrt(3)}}}
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{{{A=(1/2)(0.5X)(sqrt(3)/2)(X)}}}
{{{A=(1/2)(1/2)(44/3)sqrt(3)(22)}}}
{{{A=(242/3)sqrt(3)}}}