Question 357290
let the three consecutive integers be x , x+1 and x+2
since their sum should be  equal to 156,
          x+ (x+1) + (x+2) = 156
therefore,
          x + x + 1 + x + 2= 156
therefore,adding the like terms, we get
                    3x + 3 = 156
dividing throught the eqaution by 3, we get,
                     x + 1 = 52
 therefore, subtracting 1 from both the sides,
                         x = 51
if x= 51, x+1= 52, x+3= 53
thus,
the three integers whose sum is 156 are 51,52,53.