Question 357140
I'll do the first one to get you started.


# 1



{{{(4+i)*(2+3i)}}} Start with the given expression.



{{{(4)(2)+(4)(3i)+(i)(2)+(i)(3i)}}} FOIL.



{{{8+12i+2i+3i^2}}} Multiply.



{{{8+12i+2i+3(-1)}}} Replace {{{i^2}}} with {{{-1}}}. Note: {{{i^2=-1}}}.



{{{8+12i+2i-3}}} Multiply.



{{{5+14i}}} Combine like terms.



So {{{(4+i)*(2+3i)=5+14i}}}.