Question 357126
First, let's find the actual approximate volume of the sphere with a diameter of 8 ft. Since the diameter is 8 feet, the radius is {{{r=d/2=8/2=4}}} feet. So {{{r=4}}}



{{{V=(4/3)pi*r^3}}} Start with the volume of a sphere formula.



{{{V=(4/3)pi*(4)^3}}} Plug in {{{r=4}}}.



{{{V=(4/3)(3.14159265)*(4)^3}}} Replace {{{pi}}} with {{{3.14159265}}} (note: Use more digits of {{{pi}}} to get better accuracy).



{{{V=(4/3)(3.14159265)*(64)}}} Cube {{{4}}} to get {{{64}}}.



{{{V=(4/3)(201.0619296)}}} Multiply {{{3.14159265}}} and {{{64}}} to get {{{201.0619296}}} (this figure is approximate).



{{{V=268.0825728}}} Multiply {{{4/3}}} and {{{201.0619296}}} to get {{{268.0825728}}} (again, this figure is approximate).



So the approximate volume is 268.0825728 cubic feet which is definitely larger than 175 cubic feet.



So the balloon will stay aloft.