Question 40075
[0 0 -1]
[3 x 0 ] =x^2 
[2 0 3] 

The determinant is [ 0+0+0]-[-2x+0+0]=2x

So, 2x=x^2
x^2-2x=0
x(x-2)=0
x=0 or x=2

Cheers,
Stan H.