Question 356975
{{{sqrt(y+4)+6=7}}}
{{{sqrt(y+4)=1}}}.  Squaring both sides tyo eliminate the radical, 
{{{y+4=1}}},
{{{y = -3}}}.  This value satisfies the original equation, so this is the final answer.
{{{3+sqrt(z-6)=sqrt(z+9)}}}.
Squaring both sides, {{{9 + 6*sqrt(z-6) +z-6 = z+9}}},
{{{3+6*sqrt(z-6) = 9}}},
{{{6*sqrt(z-6) = 6}}},
{{{sqrt(z-6) = 1}}},
{{{z-6=1}}},
{{{z=7}}}.  This value satisfies the original equation, so this is the final answer.