Question 356980
Find three consecutive odd integers such that the sum of the first integer twice the second integer and three times the third is 70?

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let the integers be x,x+2,x+4
x+2(x+2)+3(x+4)=70
x+2x+4+3x+12=70
6x+16=70
add -16
6x+16-16=70-16
6x=54
/6
x= 9
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the integers are 9,11,13