Question 356900
{{{ ((m^2n^3)/p^3) /( (mp)/n^2)=((m^2n^3)/p^3) *(n^2/(mp))}}}

{{{ ((m^2n^3)/p^3) /( (mp)/n^2)=m^(2-1)n^(3+2)p^(-3-1)}}}
{{{ ((m^2n^3)/p^3) /( (mp)/n^2)=highlight((mn^5)/p^4)}}}