Question 356877
{{{(17u^5y^3+10u^3y^2) / (-2u^5y^3)=-(17/2)u^(5-5)y^(3-3)-(10/2)u^(3-5)y^(2-3)}}}
{{{(17u^5y^3+10u^3y^2) / (-2u^5y^3)=-(17/2)u^(0)y^(0)-(5)u^(-2)y^(-1)}}}
{{{(17u^5y^3+10u^3y^2) / (-2u^5y^3)=-5/(u^2y)-17/2}}}