Question 356851
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Hi,
{{{x^2/2^2-y^2/2^2=1}}} is the sames as 
{{{(x^2/4)-(y^2/4)=1}}} or {{{x^2-y^2= 4}}}
.
adding {{{x^2+ y^2=4}}} and {{{x^2-y^2= 4}}}
{{{2x^2 = 8}}}
{{{x^2 = 4}}}

x = +- 2
y = +- 2