Question 356841
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Hi,
distance between Pt(2,5)and Pt(5,9)
note: diffence in x values is 3 and difference in y values is 4
Applying the Pythagorean Theorem with c being the distance between the points
{{{3^2 + 4^2 = c^2}}}
{{{ 25= c^2}}}
c = 5

{{{drawing(300,300, -12, 12, -12, 12,
circle(5, 9,0.2),
circle(2, 5,0.2),
graph( 300, 300, -12, 12, -12, 12))}}}