Question 356835

speed of A is 40 and speed of B is 60 miles/h.

relative velocity = 60 -40 = 20 miles/h.


As train A passes the station before 15 minutes than B, so we firstly find the 

distance traveled by A during this time = 40/4 = 10 miles (15 minutes = 1/4 hour) 


now we find time when B will catch A = distance/speed 

= 10/20 = 1/2 hour

1/2 hour after 2:30  is 3:00

 
so, B will catch the A at 3:00 am.


Sometimes there may be typing mistake in solution of a problem, so please ignore it. Understand the concept and try to solve the problem yourself. If there is problem related to concept, contact at 
sudhanshu.cochin@yahoo.com or sudhanshu.cochin@gmail.com 
Best of luck.......