Question 356836

Let the length is x cm and width is y cm.

then perimeter 2(x+y) =64 cm

=> x+y = 64/2 = 32

=> x + y = 32 .............(1)


and according to  question twice the width is 4cm more than length so,


2y = x + 4  

=>  2y -x = 4  .............(2)

now we add these two equation to find the value of x and y.

3y = 36 

=> y = 12  

now put the value of y on any equation to find value of x ,

 x +12 = 32 

=> x = 32 -12 = 20 


so length is 20cm and width is 12cm.