Question 356800
F(x) = -2x^2 + 2x + 8 
----
You did not say what you want to do with this quadratic.
---
Graph:
{{{graph(400,300,-10,10,-10,10,-2x^2+2x+8)}}}
===================================================
Y-intercept: If x = 0, y = 8
X-intercept: If y = 0, x = ?
Solve -2x^2+2x+8 = 0
-2(x^2-x-4) = 0
Quad. Formula:
x = [1 +- sqrt(1-4*-4)/2
x = [1+-sqrt(17)]/2
------------------------
Cheers,
Stan H.