Question 356768
{{{(8-3i)/(2+3i)=((8-3i)/(2+3i))*((2-3i)/(2-3i))}}}
{{{(8-3i)/(2+3i)=(16-24i-6i+9i^2)/(4-6i+6i-9i^2)}}}
{{{(8-3i)/(2+3i)=(16-30i-9)/(4+9)}}}
{{{(8-3i)/(2+3i)=(7-30i)/(13)}}}
{{{highlight((8-3i)/(2+3i)=7/13-(30/13)i)}}}