Question 356642
find the value of "c" such that each pair of points is 5 units apart. 
first pair: (5,2) (c,-3)
distance = sqrt[(change in x)^2+(change in y)^2]
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5 = sqrt[(c-5)^2+(2--3)^2]
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5 = sqrt[c^2-10c+25 + 25]
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5 = sqrt[c^2-10c+50]
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c^2-10c+50= 25
c^2-10c+25 = 0
(c-5)^2 = 0
c = 5
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second pair: (0,c) (3,1)
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5 = sqrt[(3^2)+(c-1)^2]
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5 = sqrt[9+c^2-2c+1]
25 = c^2-2c+10
c^2-2c-15 = 0
(c-5)(c+3) = 0
c = 5 of c= -3
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Cheers,
Stan H.