Question 356435
Write the inverse for the function of 
y+2=4^(x-1) in the form y=.
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1st: Interchange x and y to get:
x + 2 = 4^(y-1)
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2nd: Solve for "y":
Take the log of both sides to get:
(y-1)*log(4) = log(x+2)
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y-1 = [log(x+2)/log(4)]
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y = [log(x+2)/log(4)] + 1
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That is the inverse.
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Cheers,
Stan H.