Question 356427
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Hi,
Let t be the time of Angina's hose, then .80t is the time for Brad's hose
{{{(1/.8t) + (1/t) = (1/18)}}}
multiply each term on both sides of the equation by .8*18*t
{{{18 + .8 *18 = .8t}}}
{{{32.4 = .8t }}}
t = 40.5 hr
Angina's hose takes 40.5 hr alone
Brad's hose takes .8*40.5 = 32.4 hr alone