Question 356296
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Hi,
*Assumming these expressions are both equal to 0
{{{r^2 - 5r + 6 = 0}}}
(r- 6)(r + 1)= 0
r = 6
r = -1
.
{{{r^2 - 4)}}}
(r- 2)(r + 2) = 0
r = 2
r = -2