Question 356096
f(x) = (3 + sqrt(36-x^2 ))/(x^2- 9)
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The denominator cannot equal zero.
x^2-9=(x+3)(x-3) 
(x+3)(x-3)=0
x=3, x=-3
So x cannot equal -3 or 3.
The domain of x is all real numbers except -3 and 3.
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Ed
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{{{graph(500,500,-10,10,-10,10,(3 + sqrt(36-x^2 ))/(x^2- 9))}}}