Question 39915
{{{((x^2 + 2x - 3)/(x + 2)) ((x^2 + 2x)/(x^2 - 1))}}}
{{{(((x+3)(x-1))/(x+2)) (x(x+2)/((x+1)(x-1)))}}}
The (x+2) brackets cancel top and bottom. So also do the (x-1) brackets. This leaves,
{{{(x(x+3)) /(x+1))}}}