Question 355870
Hi,
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If I am understanding your question properly
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{{{1/8(B-9) = B+9}}}
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First clearing the denomiator:
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multiplying both sides of the equation by 8(B -9)
{{{1 = 8(B-9)*(B+9)}}}
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Simplifying
{{{ 1 = 8(B^2 -81)}}}
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{{{ 1 = 8B^2 - 648}}}
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{{{649 = 8B^2}}}
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{{{81 = B^2}}}
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{{{9= B}}}