Question 355742
Hi,

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{{{25=4^(2x-3)}}}
Let(2x-3) = n
{{{4^n = 25}}}
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taking the log of both sides, using a log of base 4. 
*[tex \large \ \ log_4(4)^n = log_4(25)]
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*[tex \large \ \ n = log_4(25)]
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*[tex \large n = log_4(25)= log (25)/log(4)= 2.322 ]
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(2x-3) = n
(2x-3) = 2.322
solve for x