Question 355705
(4y+3xy^2) (4y-3xy^2)
to put in simple terms you have to multiply each term in one bracket with the other terms in the second bracket.
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4y(4y-3xy^2)+3xy^2(4y-3xy^2)
now you have to multiply the term outside the bracket with the terms in the bracket.( distributive law)
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4y*4y-4y*3xy^2+3xy^2*4y-3xy^2*3xy^2
16y^2-12xy^3+12xy^3-9x^2y^4
16y^2-9x^2y^4
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