Question 355710
HI

Note: The probability of x successes in n trials is: 
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P = nCx* {{{p^x}}}*{{{q^(n-x)}}} where p and q are the probabilities of success and failure respectively. In this case both p =.35 q = .65
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nCx = {{{n!/(x!(n-x!))}}} 
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9C2 = 9!/(2!7!) = 9*4 = 36
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P (2 successes in 9 trials) = 36* {{{.35^2}}}*{{{.65^(7)}}}