Question 355697
Hi,
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Solving for the "three" solutions of this cubic equation
{{{ 8x^3-1=0 }}}
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{{{ x^3 -(1/8)^3 = 0 }}}
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{{{ (x- 1/2)*(x^2 + (1/2)x + 1/4 )= 0 }}}
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{{{(x- 1/2)=0}}}  x = (1/2)
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{{{(x^2 + (1/2)x + 1/4)= 0 }}}
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solving using the quadratic equation results in 2 non-real numbers
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
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{{{x = (-.5 +- i*sqrt( .75 ))/(2) }}}