Question 355553
points (-2,2) (0,5)
slope m = y2-y1/x2-x1
slope = 5-2/0+2
= 3/2
...
equation = (y-y1)=m(x-x1)
use the first point
(y-2)=3/2(x+2)
2(y-2)=3(x+2)
2y-4 = 3x+6
2y= 3x+10
y = 3/2 *x +5is the equation of the line
{{{graph(300,300,-5,5,-5,7,((3x/2)+5))}}}