Question 355288
Slightly out of order, but it's all there,
.
.
.
When {{{x=0}}}, {{{2y=-2}}}, {{{y=-1}}}:({{{0}}},{{{-1}}})
When {{{y=0}}}, {{{x=-2}}}:({{{-2}}},{{{0}}}).
.
.
{{{2y+x=-2}}}
{{{-2y=x+2}}}
{{{highlight(y=-(1/2)x-1)}}}
.
.
.
Plot the intercepts from above and connect the points with a straight line.
.
.
.
{{{drawing(300,300,-5,5,-5,5,grid(1),circle(0,-1,0.2),circle(-2,0,0.2),graph(300,300,-5,5,-5,5,-(1/2)x-1))}}}