Question 355234
Each number is equally likely,
{{{P(x)=0.1}}}, for {{{x=1-10}}}.
.
.
.
{{{P(x<4)=P(1)+P(2)+P(3)=0.30}}}
.
.
.
Mean={{{mu=sum(x*P(x),i=1,10)=5.5}}}
.
.
.
Var={{{sum((x-mu)^2*P(x),i=1,10)=8.25}}}