Question 355171
Hi,
Note: The probability of x successes in n trials is: 
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P = nCx* {{{p^x}}}*{{{q^(n-x)}}} where p and q are the probabilities of success and failure respectively. In this case p(a women chosen) = 4/7 and q = 3/7
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nCx = {{{n!/(x!(n-x!))}}}
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1) P(all three selected will be women) = {{{(4/7)^3}}}
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2) P(all three selected will be men) = {{{(3/7)^3}}}
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3) P(two men and one woman will be selected) = {{{3*(4/7)^1 *( 3/7)^2}}}
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4) P(one man and two women will be selected) = {{{3*(4/7)^2 * (3/7)^1}}}