Question 355104
Let x = # of grams of 50% silver alloy
Then 24 - x = # of grams of 10% silver alloy.
{{{0.50x+0.10(24 - x) = 0.25*24}}},
{{{0.50x+2.4 - 0.10x = 6}}}
{{{0.40x = 3.6}}},
{{{x = 9}}}, and {{{24 - x = 24-9 =15}}}.
Therefore he has to mix 9 grams of 50% silver alloy, and 15 grams of 10% silver alloy.