Question 355059
{{{5^(x+3) = 8^(2x-1)}}}.
Take log of both sides:
{{{(x+3)*log5 = (2x-1)*log8}}}
{{{x*log5+3log5 = 2x*log8-log8}}}
{{{x*log5 - 2x*log8 = -log8-3log5}}}
{{{(log5-2log8)*x = -log8-3log5}}}
{{{x = (-log8-3log5)/(log5-2log8)}}}