<PRE><B>Question 355009</B>
 The Tennessee Tourism Institute (TTI) plans to sample information center visitors entering the state to learn the fraction of visitors who plan to camp in the state. Current estimates are that 32 percent of visitors are campers.

How large a sample would you take to estimate at a 90 percent confidence level the population proportion with an allowable error of 2 percent?
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E = z*sqrt(pq/n)
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n = [z/E]^2(pq)
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n = [1.645/0.02]^2(0.32*0.68)
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n = 1472 when rounded up
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Cheers,
Stan H.</PRE>