Question 355007
y= {{{5x^2+10x+7}}}. I must write the quadratic equation into vertex form and find the vertex. 
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5x^2+10x+7 = y
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5x^2+10x = y - 7
5(x^2+2x+1) = y-7+5*1
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5(x+1)^2 = y-2
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Vertex: (-1,2)
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{{{graph(400,300,-10,10,-10,10,5x^2+10x+7)}}}}
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Cheers,
Stan H.