<PRE><B>Question 354971</B>
The sum of two consecutive terms in the arithmetic 
sequence 1,4,7,10,,, is 299 find these two terms?
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a(1) = 1
d = 4-1 = 3
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Two consecutive terms would be:
a(n) = a(1)+(n-1)d
a(n+1) = a(1)+(n)d
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Equation: 
1 + (n-1)3 + 1+3n = 299
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2 + 3n-3 + 3n = 299
6n = 300
n = 50
n+1 = 51
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a(50) = 1 + 49*3 = 148
a(51) = 148+3 = 151
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Check:
148+151 = 299
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cheers,
Stan H.</PRE>