Question 354955
{{{2p^2=6p-20}}}
Dividing both sides by 2, we get
{{{p^2=3p-10}}},
{{{p^2-3p+10=0}}}.  Using the quadratic formula,
{{{p=(3+-sqrt(9-4*1*10))/2}}}
{{{p=(3+-sqrt(-31))/2}}}

{{{p=(3+-i*sqrt(31))/2}}}