Question 354652
Pick three 'easy' values for x and then solve for y.
Also, the y intercept occurs when the value for x is zero.

{{{y=(3/2)x+3 }}}
let x = 0
{{{y=(3/2)*0+3 }}}
{{{y=3}}}
y intercept and one point is (0,3)
let x = 1
{{{y=(3/2)x+3 }}}
{{{y=(3/2)*1+3 }}}
{{{y = (3/2) + 3}}}
{{{y = 9/2}}}
Another point is (1, 9/2)
Let x = -1
{{{y=(3/2)x+3 }}}
{{{y = (3/2) * (-1) + 3}}}
{{{y = -(3/2) + 3}}}
{{{y = 3/2}}}
Third point is (-1, 3/2)
{{{graph(400,400,-10,10,-10,10, 3x/2 + 3)}}}