Question 354620
A football field is rectangular with a perimeter of 1040 feet. the length is 200 feet more than the width. Find the length and the width of the field. (hint: p=2l+2w)
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Let the width be "w".
Then the length is "w+200"
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P = 2(l+w)
1040 = 2(w+200 + w)
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520 = 2w+200
2w = 320
w = 160 (width)
l = w+200 = 360 (length)
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cheers,
Stan H.