Question 354499
{{{log((x+9))+ log x = 1}}},
{{{log(x(x+9)) = 1}}},
{{{10^1 = x(x+9)}}},or
{{{x^2+9x-10=0}}}
{{{(x+10)(x-1)=0}}},
{{{x = -10}}}, or {{{x = 1}}}.
Eliminate {{{x = -10}}}, as it is an extraneous root (won't satisfy the original equation.)  Therefore the solution is {{{x = 1}}}.