Question 354379
{{{(x+2)(x-2)/(2x^2+8x+8)+(-5)/(x+2)=-1/(2x+4)}}},
{{{((x+2)(x-2))/(2*(x+2)^2)-5/(x+2)=-1/(2(x+2))}}}.  
Assuming that x is not equal to -2, the equation becomes
{{{(x-2)/(2(x+2))-5/(x+2) = -1/(2(x+2))}}}, or
{{{(x-2)/(2(x+2))-10/(2(x+2)) = -1/(2(x+2))}}}.
Putting the equation in standard form , we get
{{{(x-2-10+1)/(2(x+2)) = 0}}}, or {{{(x-11)/(2(x+2)) = 0}}}.
Then we would get {{{x - 11=0}}}, and so {{{x = 11}}}.  Since 11 is not equal to 2, the final answer for x is 11.