Question 39876
Let us clear all of the fractions in
x/3 + 1/6 ≤ 2x + 3/2
by multiplying by the lowest common denominator, which is 6...we get
6[x/3 + 1/6 ≤ 2x + 3/2]
2x + 1 ≤ 12x + 9
-8 ≤ 10x
-4/5 ≤ x or
x ≥ -4/5