Question 352196

This problem is just like arrange 2 C's, 3 D's and 5 F's in a row i.e the no. of 

words of 10 letters that can be found from these letters.

CCDDDFFFFF, DDCFCFDFFF, DFCDFCDFFF, ...............and so on.



no. of ways = 10! / (2! * 3! * 5!)

= 2520



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