Question 354049
2(x-4)-(x+2)=(x+2)(x-4)
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2x-8-x-2=x^2-2x-8
x^2-3x+2=0
x^2-2x-x+2=0
x(x-2)-1(x-2)=0
(x-2)(x-1)=0
x = 1, 2
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