Question 353894
Well, you are ok so far but now you can use the quadratic formula ({{{y = (-b+-sqrt(b^2-4ac))/2a}}}) to solve for y.  In this problem, a = 2, b = 5, and c = -13, so...
{{{y = (-5+-sqrt(5^2-4(2)(-13)))/2(2)}}}
When you evaluate this you will get:
{{{y = -4.089}}} or {{{1.589}}}
Now you will need to substitute {{{y = x^(2/3)}}}, so...
{{{x^(2/3) = -4.089}}} or {{{x^(2/3) = 1.589}}}
To find x, raise both sides of each solution to the {{{3/2}}} (the reciprocal of {{{2/3)}}}) power.
{{{x = (-4.089)^(3/2)}}} or {{{x = (1.589)^(3/2)}}} Use your calculator to evaluate to get:
{{{x = -8.268i}}} or {{{x = 2}}}
It would be advisable to check these solutions in your original equations.